3.26.34 \(\int (a+b x)^{-n} (c+d x) (e+f x)^{-5+n} \, dx\)

Optimal. Leaf size=300 \[ \frac {2 b^2 (a+b x)^{1-n} (e+f x)^{n-1} (b (3 c f+d e (1-n))-a d f (4-n))}{f (1-n) (2-n) (3-n) (4-n) (b e-a f)^4}-\frac {(a+b x)^{1-n} (d e-c f) (e+f x)^{n-4}}{f (4-n) (b e-a f)}+\frac {(a+b x)^{1-n} (e+f x)^{n-3} (b (3 c f+d e (1-n))-a d f (4-n))}{f (3-n) (4-n) (b e-a f)^2}+\frac {2 b (a+b x)^{1-n} (e+f x)^{n-2} (b (3 c f+d e (1-n))-a d f (4-n))}{f (2-n) (3-n) (4-n) (b e-a f)^3} \]

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Rubi [A]  time = 0.19, antiderivative size = 297, normalized size of antiderivative = 0.99, number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {79, 45, 37} \begin {gather*} \frac {2 b^2 (a+b x)^{1-n} (e+f x)^{n-1} (-a d f (4-n)+3 b c f+b d e (1-n))}{f (1-n) (2-n) (3-n) (4-n) (b e-a f)^4}-\frac {(a+b x)^{1-n} (d e-c f) (e+f x)^{n-4}}{f (4-n) (b e-a f)}+\frac {(a+b x)^{1-n} (e+f x)^{n-3} (-a d f (4-n)+3 b c f+b d e (1-n))}{f (3-n) (4-n) (b e-a f)^2}+\frac {2 b (a+b x)^{1-n} (e+f x)^{n-2} (-a d f (4-n)+3 b c f+b d e (1-n))}{f (2-n) (3-n) (4-n) (b e-a f)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((c + d*x)*(e + f*x)^(-5 + n))/(a + b*x)^n,x]

[Out]

-(((d*e - c*f)*(a + b*x)^(1 - n)*(e + f*x)^(-4 + n))/(f*(b*e - a*f)*(4 - n))) + ((3*b*c*f + b*d*e*(1 - n) - a*
d*f*(4 - n))*(a + b*x)^(1 - n)*(e + f*x)^(-3 + n))/(f*(b*e - a*f)^2*(3 - n)*(4 - n)) + (2*b*(3*b*c*f + b*d*e*(
1 - n) - a*d*f*(4 - n))*(a + b*x)^(1 - n)*(e + f*x)^(-2 + n))/(f*(b*e - a*f)^3*(2 - n)*(3 - n)*(4 - n)) + (2*b
^2*(3*b*c*f + b*d*e*(1 - n) - a*d*f*(4 - n))*(a + b*x)^(1 - n)*(e + f*x)^(-1 + n))/(f*(b*e - a*f)^4*(1 - n)*(2
- n)*(3 - n)*(4 - n))

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rule 79

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^Simplify[p + 1], x], x] /; FreeQ[{a, b, c,
d, e, f, n, p}, x] &&  !RationalQ[p] && SumSimplerQ[p, 1]

Rubi steps

\begin {align*} \int (a+b x)^{-n} (c+d x) (e+f x)^{-5+n} \, dx &=-\frac {(d e-c f) (a+b x)^{1-n} (e+f x)^{-4+n}}{f (b e-a f) (4-n)}-\frac {(-3 b c f-d (b e (1-n)+a f (-4+n))) \int (a+b x)^{-n} (e+f x)^{-4+n} \, dx}{f (-b e+a f) (-4+n)}\\ &=-\frac {(d e-c f) (a+b x)^{1-n} (e+f x)^{-4+n}}{f (b e-a f) (4-n)}+\frac {(3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-3+n}}{f (b e-a f)^2 (3-n) (4-n)}-\frac {(2 b (-3 b c f-d (b e (1-n)+a f (-4+n)))) \int (a+b x)^{-n} (e+f x)^{-3+n} \, dx}{f (b e-a f) (-b e+a f) (3-n) (-4+n)}\\ &=-\frac {(d e-c f) (a+b x)^{1-n} (e+f x)^{-4+n}}{f (b e-a f) (4-n)}+\frac {(3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-3+n}}{f (b e-a f)^2 (3-n) (4-n)}+\frac {2 b (3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-2+n}}{f (b e-a f)^3 (2-n) (3-n) (4-n)}-\frac {\left (2 b^2 (-3 b c f-d (b e (1-n)+a f (-4+n)))\right ) \int (a+b x)^{-n} (e+f x)^{-2+n} \, dx}{f (b e-a f)^2 (-b e+a f) (2-n) (3-n) (-4+n)}\\ &=-\frac {(d e-c f) (a+b x)^{1-n} (e+f x)^{-4+n}}{f (b e-a f) (4-n)}+\frac {(3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-3+n}}{f (b e-a f)^2 (3-n) (4-n)}+\frac {2 b (3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-2+n}}{f (b e-a f)^3 (2-n) (3-n) (4-n)}+\frac {2 b^2 (3 b c f+b d e (1-n)-a d f (4-n)) (a+b x)^{1-n} (e+f x)^{-1+n}}{f (b e-a f)^4 (1-n) (2-n) (3-n) (4-n)}\\ \end {align*}

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Mathematica [A]  time = 0.50, size = 145, normalized size = 0.48 \begin {gather*} \frac {(a+b x)^{1-n} (e+f x)^{n-4} \left (-\frac {(e+f x) \left ((n-2) (n-1) (b e-a f)^2-2 b (e+f x) (-a f (n-1)+b e (n-2)-b f x)\right ) (a d f (n-4)+3 b c f-b d e (n-1))}{(n-3) (n-2) (n-1) (b e-a f)^3}+c f-d e\right )}{f (n-4) (a f-b e)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((c + d*x)*(e + f*x)^(-5 + n))/(a + b*x)^n,x]

[Out]

((a + b*x)^(1 - n)*(e + f*x)^(-4 + n)*(-(d*e) + c*f - ((3*b*c*f + a*d*f*(-4 + n) - b*d*e*(-1 + n))*(e + f*x)*(
(b*e - a*f)^2*(-2 + n)*(-1 + n) - 2*b*(e + f*x)*(b*e*(-2 + n) - a*f*(-1 + n) - b*f*x)))/((b*e - a*f)^3*(-3 + n
)*(-2 + n)*(-1 + n))))/(f*(-(b*e) + a*f)*(-4 + n))

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IntegrateAlgebraic [F]  time = 0.07, size = 0, normalized size = 0.00 \begin {gather*} \int (a+b x)^{-n} (c+d x) (e+f x)^{-5+n} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[((c + d*x)*(e + f*x)^(-5 + n))/(a + b*x)^n,x]

[Out]

Defer[IntegrateAlgebraic][((c + d*x)*(e + f*x)^(-5 + n))/(a + b*x)^n, x]

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fricas [B]  time = 1.30, size = 1740, normalized size = 5.80

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*(f*x+e)^(-5+n)/((b*x+a)^n),x, algorithm="fricas")

[Out]

-(6*a^4*c*e*f^3 - 2*(b^4*d*e*f^3 + (3*b^4*c - 4*a*b^3*d)*f^4 - (b^4*d*e*f^3 - a*b^3*d*f^4)*n)*x^5 - 12*(2*a*b^
3*c - a^2*b^2*d)*e^4 + 4*(9*a^2*b^2*c - 2*a^3*b*d)*e^3*f - 2*(12*a^3*b*c - a^4*d)*e^2*f^2 - 2*(5*b^4*d*e^2*f^2
+ 5*(3*b^4*c - 4*a*b^3*d)*e*f^3 + (b^4*d*e^2*f^2 - 2*a*b^3*d*e*f^3 + a^2*b^2*d*f^4)*n^2 - (6*b^4*d*e^2*f^2 +
(3*b^4*c - 10*a*b^3*d)*e*f^3 - (3*a*b^3*c - 4*a^2*b^2*d)*f^4)*n)*x^4 + (a*b^3*c*e^4 - 3*a^2*b^2*c*e^3*f + 3*a^
3*b*c*e^2*f^2 - a^4*c*e*f^3)*n^3 - (20*b^4*d*e^3*f + 20*(3*b^4*c - 4*a*b^3*d)*e^2*f^2 - (b^4*d*e^3*f - 3*a*b^3
*d*e^2*f^2 + 3*a^2*b^2*d*e*f^3 - a^3*b*d*f^4)*n^3 + (10*b^4*d*e^3*f + (3*b^4*c - 25*a*b^3*d)*e^2*f^2 - 2*(3*a*
b^3*c - 10*a^2*b^2*d)*e*f^3 + (3*a^2*b^2*c - 5*a^3*b*d)*f^4)*n^2 - (29*b^4*d*e^3*f + 3*(9*b^4*c - 22*a*b^3*d)*
e^2*f^2 - (30*a*b^3*c - 41*a^2*b^2*d)*e*f^3 + (3*a^2*b^2*c - 4*a^3*b*d)*f^4)*n)*x^3 + (6*a^4*c*e*f^3 - (9*a*b^
3*c - a^2*b^2*d)*e^4 + 2*(12*a^2*b^2*c - a^3*b*d)*e^3*f - (21*a^3*b*c - a^4*d)*e^2*f^2)*n^2 - (12*b^4*d*e^4 -
48*a^2*b^2*d*e^2*f^2 + 32*a^3*b*d*e*f^3 - 8*a^4*d*f^4 + 12*(5*b^4*c - 4*a*b^3*d)*e^3*f - (b^4*d*e^4 - 3*a*b^3*
c*e^2*f^2 + (b^4*c - 2*a*b^3*d)*e^3*f + (3*a^2*b^2*c + 2*a^3*b*d)*e*f^3 - (a^3*b*c + a^4*d)*f^4)*n^3 + (8*b^4*
d*e^4 + 2*(6*b^4*c - 7*a*b^3*d)*e^3*f - 3*(9*a*b^3*c + a^2*b^2*d)*e^2*f^2 + 2*(9*a^2*b^2*c + 8*a^3*b*d)*e*f^3
- (3*a^3*b*c + 7*a^4*d)*f^4)*n^2 - (19*b^4*d*e^4 + (47*b^4*c - 36*a*b^3*d)*e^3*f - 15*(4*a*b^3*c + a^2*b^2*d)*
e^2*f^2 + (15*a^2*b^2*c + 46*a^3*b*d)*e*f^3 - 2*(a^3*b*c + 7*a^4*d)*f^4)*n)*x^2 - (11*a^4*c*e*f^3 - (26*a*b^3*
c - 7*a^2*b^2*d)*e^4 + (57*a^2*b^2*c - 10*a^3*b*d)*e^3*f - 3*(14*a^3*b*c - a^4*d)*e^2*f^2)*n - (24*b^4*c*e^4 -
6*a^4*c*f^4 + 12*(2*a*b^3*c - 5*a^2*b^2*d)*e^3*f - 4*(9*a^2*b^2*c - 10*a^3*b*d)*e^2*f^2 + 2*(12*a^3*b*c - 5*a
^4*d)*e*f^3 - (3*a^3*b*d*e^2*f^2 - a^4*c*f^4 + (b^4*c + a*b^3*d)*e^4 - (2*a*b^3*c + 3*a^2*b^2*d)*e^3*f + (2*a^
3*b*c - a^4*d)*e*f^3)*n^3 - (6*a^4*c*f^4 - (9*b^4*c + 7*a*b^3*d)*e^4 + 2*(6*a*b^3*c + 11*a^2*b^2*d)*e^3*f + (9
*a^2*b^2*c - 23*a^3*b*d)*e^2*f^2 - 2*(9*a^3*b*c - 4*a^4*d)*e*f^3)*n^2 + (11*a^4*c*f^4 - 2*(13*b^4*c + 6*a*b^3*
d)*e^4 + 5*(2*a*b^3*c + 11*a^2*b^2*d)*e^3*f + 15*(3*a^2*b^2*c - 4*a^3*b*d)*e^2*f^2 - (40*a^3*b*c - 17*a^4*d)*e
*f^3)*n)*x)*(f*x + e)^(n - 5)/((24*b^4*e^4 - 96*a*b^3*e^3*f + 144*a^2*b^2*e^2*f^2 - 96*a^3*b*e*f^3 + 24*a^4*f^
4 + (b^4*e^4 - 4*a*b^3*e^3*f + 6*a^2*b^2*e^2*f^2 - 4*a^3*b*e*f^3 + a^4*f^4)*n^4 - 10*(b^4*e^4 - 4*a*b^3*e^3*f
+ 6*a^2*b^2*e^2*f^2 - 4*a^3*b*e*f^3 + a^4*f^4)*n^3 + 35*(b^4*e^4 - 4*a*b^3*e^3*f + 6*a^2*b^2*e^2*f^2 - 4*a^3*b
*e*f^3 + a^4*f^4)*n^2 - 50*(b^4*e^4 - 4*a*b^3*e^3*f + 6*a^2*b^2*e^2*f^2 - 4*a^3*b*e*f^3 + a^4*f^4)*n)*(b*x + a
)^n)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (d x + c\right )} {\left (f x + e\right )}^{n - 5}}{{\left (b x + a\right )}^{n}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*(f*x+e)^(-5+n)/((b*x+a)^n),x, algorithm="giac")

[Out]

integrate((d*x + c)*(f*x + e)^(n - 5)/(b*x + a)^n, x)

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maple [B]  time = 0.01, size = 1188, normalized size = 3.96 \begin {gather*} \frac {\left (b x +a \right ) \left (a^{3} d \,f^{3} n^{3} x -3 a^{2} b d e \,f^{2} n^{3} x +2 a^{2} b d \,f^{3} n^{2} x^{2}+3 a \,b^{2} d \,e^{2} f \,n^{3} x -4 a \,b^{2} d e \,f^{2} n^{2} x^{2}+2 a \,b^{2} d \,f^{3} n \,x^{3}-b^{3} d \,e^{3} n^{3} x +2 b^{3} d \,e^{2} f \,n^{2} x^{2}-2 b^{3} d e \,f^{2} n \,x^{3}+a^{3} c \,f^{3} n^{3}-7 a^{3} d \,f^{3} n^{2} x -3 a^{2} b c e \,f^{2} n^{3}+3 a^{2} b c \,f^{3} n^{2} x +22 a^{2} b d e \,f^{2} n^{2} x -10 a^{2} b d \,f^{3} n \,x^{2}+3 a \,b^{2} c \,e^{2} f \,n^{3}-6 a \,b^{2} c e \,f^{2} n^{2} x +6 a \,b^{2} c \,f^{3} n \,x^{2}-23 a \,b^{2} d \,e^{2} f \,n^{2} x +20 a \,b^{2} d e \,f^{2} n \,x^{2}-8 a \,b^{2} d \,f^{3} x^{3}-b^{3} c \,e^{3} n^{3}+3 b^{3} c \,e^{2} f \,n^{2} x -6 b^{3} c e \,f^{2} n \,x^{2}+6 b^{3} c \,f^{3} x^{3}+8 b^{3} d \,e^{3} n^{2} x -10 b^{3} d \,e^{2} f n \,x^{2}+2 b^{3} d e \,f^{2} x^{3}-6 a^{3} c \,f^{3} n^{2}-a^{3} d e \,f^{2} n^{2}+14 a^{3} d \,f^{3} n x +21 a^{2} b c e \,f^{2} n^{2}-9 a^{2} b c \,f^{3} n x +2 a^{2} b d \,e^{2} f \,n^{2}-53 a^{2} b d e \,f^{2} n x +8 a^{2} b d \,f^{3} x^{2}-24 a \,b^{2} c \,e^{2} f \,n^{2}+30 a \,b^{2} c e \,f^{2} n x -6 a \,b^{2} c \,f^{3} x^{2}-a \,b^{2} d \,e^{3} n^{2}+58 a \,b^{2} d \,e^{2} f n x -34 a \,b^{2} d e \,f^{2} x^{2}+9 b^{3} c \,e^{3} n^{2}-21 b^{3} c \,e^{2} f n x +24 b^{3} c e \,f^{2} x^{2}-19 b^{3} d \,e^{3} n x +8 b^{3} d \,e^{2} f \,x^{2}+11 a^{3} c \,f^{3} n +3 a^{3} d e \,f^{2} n -8 a^{3} d \,f^{3} x -42 a^{2} b c e \,f^{2} n +6 a^{2} b c \,f^{3} x -10 a^{2} b d \,e^{2} f n +34 a^{2} b d e \,f^{2} x +57 a \,b^{2} c \,e^{2} f n -24 a \,b^{2} c e \,f^{2} x +7 a \,b^{2} d \,e^{3} n -56 a \,b^{2} d \,e^{2} f x -26 b^{3} c \,e^{3} n +36 b^{3} c \,e^{2} f x +12 b^{3} d \,e^{3} x -6 a^{3} c \,f^{3}-2 a^{3} d e \,f^{2}+24 a^{2} b c e \,f^{2}+8 a^{2} b d \,e^{2} f -36 a \,b^{2} c \,e^{2} f -12 a \,b^{2} d \,e^{3}+24 b^{3} c \,e^{3}\right ) \left (b x +a \right )^{-n} \left (f x +e \right )^{n -4}}{a^{4} f^{4} n^{4}-4 a^{3} b e \,f^{3} n^{4}+6 a^{2} b^{2} e^{2} f^{2} n^{4}-4 a \,b^{3} e^{3} f \,n^{4}+b^{4} e^{4} n^{4}-10 a^{4} f^{4} n^{3}+40 a^{3} b e \,f^{3} n^{3}-60 a^{2} b^{2} e^{2} f^{2} n^{3}+40 a \,b^{3} e^{3} f \,n^{3}-10 b^{4} e^{4} n^{3}+35 a^{4} f^{4} n^{2}-140 a^{3} b e \,f^{3} n^{2}+210 a^{2} b^{2} e^{2} f^{2} n^{2}-140 a \,b^{3} e^{3} f \,n^{2}+35 b^{4} e^{4} n^{2}-50 a^{4} f^{4} n +200 a^{3} b e \,f^{3} n -300 a^{2} b^{2} e^{2} f^{2} n +200 a \,b^{3} e^{3} f n -50 b^{4} e^{4} n +24 a^{4} f^{4}-96 a^{3} b e \,f^{3}+144 a^{2} b^{2} e^{2} f^{2}-96 a \,b^{3} e^{3} f +24 b^{4} e^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x+c)*(f*x+e)^(-5+n)/((b*x+a)^n),x)

[Out]

(b*x+a)*(f*x+e)^(n-4)*(a^3*d*f^3*n^3*x-3*a^2*b*d*e*f^2*n^3*x+2*a^2*b*d*f^3*n^2*x^2+3*a*b^2*d*e^2*f*n^3*x-4*a*b
^2*d*e*f^2*n^2*x^2+2*a*b^2*d*f^3*n*x^3-b^3*d*e^3*n^3*x+2*b^3*d*e^2*f*n^2*x^2-2*b^3*d*e*f^2*n*x^3+a^3*c*f^3*n^3
-7*a^3*d*f^3*n^2*x-3*a^2*b*c*e*f^2*n^3+3*a^2*b*c*f^3*n^2*x+22*a^2*b*d*e*f^2*n^2*x-10*a^2*b*d*f^3*n*x^2+3*a*b^2
*c*e^2*f*n^3-6*a*b^2*c*e*f^2*n^2*x+6*a*b^2*c*f^3*n*x^2-23*a*b^2*d*e^2*f*n^2*x+20*a*b^2*d*e*f^2*n*x^2-8*a*b^2*d
*f^3*x^3-b^3*c*e^3*n^3+3*b^3*c*e^2*f*n^2*x-6*b^3*c*e*f^2*n*x^2+6*b^3*c*f^3*x^3+8*b^3*d*e^3*n^2*x-10*b^3*d*e^2*
f*n*x^2+2*b^3*d*e*f^2*x^3-6*a^3*c*f^3*n^2-a^3*d*e*f^2*n^2+14*a^3*d*f^3*n*x+21*a^2*b*c*e*f^2*n^2-9*a^2*b*c*f^3*
n*x+2*a^2*b*d*e^2*f*n^2-53*a^2*b*d*e*f^2*n*x+8*a^2*b*d*f^3*x^2-24*a*b^2*c*e^2*f*n^2+30*a*b^2*c*e*f^2*n*x-6*a*b
^2*c*f^3*x^2-a*b^2*d*e^3*n^2+58*a*b^2*d*e^2*f*n*x-34*a*b^2*d*e*f^2*x^2+9*b^3*c*e^3*n^2-21*b^3*c*e^2*f*n*x+24*b
^3*c*e*f^2*x^2-19*b^3*d*e^3*n*x+8*b^3*d*e^2*f*x^2+11*a^3*c*f^3*n+3*a^3*d*e*f^2*n-8*a^3*d*f^3*x-42*a^2*b*c*e*f^
2*n+6*a^2*b*c*f^3*x-10*a^2*b*d*e^2*f*n+34*a^2*b*d*e*f^2*x+57*a*b^2*c*e^2*f*n-24*a*b^2*c*e*f^2*x+7*a*b^2*d*e^3*
n-56*a*b^2*d*e^2*f*x-26*b^3*c*e^3*n+36*b^3*c*e^2*f*x+12*b^3*d*e^3*x-6*a^3*c*f^3-2*a^3*d*e*f^2+24*a^2*b*c*e*f^2
+8*a^2*b*d*e^2*f-36*a*b^2*c*e^2*f-12*a*b^2*d*e^3+24*b^3*c*e^3)/(a^4*f^4*n^4-4*a^3*b*e*f^3*n^4+6*a^2*b^2*e^2*f^
2*n^4-4*a*b^3*e^3*f*n^4+b^4*e^4*n^4-10*a^4*f^4*n^3+40*a^3*b*e*f^3*n^3-60*a^2*b^2*e^2*f^2*n^3+40*a*b^3*e^3*f*n^
3-10*b^4*e^4*n^3+35*a^4*f^4*n^2-140*a^3*b*e*f^3*n^2+210*a^2*b^2*e^2*f^2*n^2-140*a*b^3*e^3*f*n^2+35*b^4*e^4*n^2
-50*a^4*f^4*n+200*a^3*b*e*f^3*n-300*a^2*b^2*e^2*f^2*n+200*a*b^3*e^3*f*n-50*b^4*e^4*n+24*a^4*f^4-96*a^3*b*e*f^3
+144*a^2*b^2*e^2*f^2-96*a*b^3*e^3*f+24*b^4*e^4)/((b*x+a)^n)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (d x + c\right )} {\left (f x + e\right )}^{n - 5}}{{\left (b x + a\right )}^{n}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*(f*x+e)^(-5+n)/((b*x+a)^n),x, algorithm="maxima")

[Out]

integrate((d*x + c)*(f*x + e)^(n - 5)/(b*x + a)^n, x)

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mupad [B]  time = 4.56, size = 1659, normalized size = 5.53

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((e + f*x)^(n - 5)*(c + d*x))/(a + b*x)^n,x)

[Out]

(2*b^3*f^3*x^5*(e + f*x)^(n - 5)*(3*b*c*f - 4*a*d*f + b*d*e + a*d*f*n - b*d*e*n))/((a*f - b*e)^4*(a + b*x)^n*(
35*n^2 - 50*n - 10*n^3 + n^4 + 24)) - (x*(e + f*x)^(n - 5)*(6*a^4*c*f^4 - 24*b^4*c*e^4 + 6*a^4*c*f^4*n^2 - 9*b
^4*c*e^4*n^2 - a^4*c*f^4*n^3 + b^4*c*e^4*n^3 + 10*a^4*d*e*f^3 - 11*a^4*c*f^4*n + 26*b^4*c*e^4*n - 24*a*b^3*c*e
^3*f - 24*a^3*b*c*e*f^3 + 12*a*b^3*d*e^4*n - 17*a^4*d*e*f^3*n + 60*a^2*b^2*d*e^3*f - 40*a^3*b*d*e^2*f^2 - 7*a*
b^3*d*e^4*n^2 + a*b^3*d*e^4*n^3 + 8*a^4*d*e*f^3*n^2 - a^4*d*e*f^3*n^3 + 36*a^2*b^2*c*e^2*f^2 - 45*a^2*b^2*c*e^
2*f^2*n + 22*a^2*b^2*d*e^3*f*n^2 - 23*a^3*b*d*e^2*f^2*n^2 - 3*a^2*b^2*d*e^3*f*n^3 + 3*a^3*b*d*e^2*f^2*n^3 - 10
*a*b^3*c*e^3*f*n + 40*a^3*b*c*e*f^3*n + 9*a^2*b^2*c*e^2*f^2*n^2 + 12*a*b^3*c*e^3*f*n^2 - 18*a^3*b*c*e*f^3*n^2
- 2*a*b^3*c*e^3*f*n^3 + 2*a^3*b*c*e*f^3*n^3 - 55*a^2*b^2*d*e^3*f*n + 60*a^3*b*d*e^2*f^2*n))/((a*f - b*e)^4*(a
+ b*x)^n*(35*n^2 - 50*n - 10*n^3 + n^4 + 24)) - (x^2*(e + f*x)^(n - 5)*(8*a^4*d*f^4 - 12*b^4*d*e^4 + 7*a^4*d*f
^4*n^2 - 8*b^4*d*e^4*n^2 - a^4*d*f^4*n^3 + b^4*d*e^4*n^3 - 60*b^4*c*e^3*f - 14*a^4*d*f^4*n + 19*b^4*d*e^4*n +
48*a*b^3*d*e^3*f - 32*a^3*b*d*e*f^3 - 2*a^3*b*c*f^4*n + 47*b^4*c*e^3*f*n + 3*a^3*b*c*f^4*n^2 - a^3*b*c*f^4*n^3
- 12*b^4*c*e^3*f*n^2 + b^4*c*e^3*f*n^3 + 48*a^2*b^2*d*e^2*f^2 + 27*a*b^3*c*e^2*f^2*n^2 - 18*a^2*b^2*c*e*f^3*n
^2 - 3*a*b^3*c*e^2*f^2*n^3 + 3*a^2*b^2*c*e*f^3*n^3 - 15*a^2*b^2*d*e^2*f^2*n - 36*a*b^3*d*e^3*f*n + 46*a^3*b*d*
e*f^3*n + 3*a^2*b^2*d*e^2*f^2*n^2 - 60*a*b^3*c*e^2*f^2*n + 15*a^2*b^2*c*e*f^3*n + 14*a*b^3*d*e^3*f*n^2 - 16*a^
3*b*d*e*f^3*n^2 - 2*a*b^3*d*e^3*f*n^3 + 2*a^3*b*d*e*f^3*n^3))/((a*f - b*e)^4*(a + b*x)^n*(35*n^2 - 50*n - 10*n
^3 + n^4 + 24)) - ((e + f*x)^(n - 5)*(12*a^2*b^2*d*e^4 + 2*a^4*d*e^2*f^2 - 24*a*b^3*c*e^4 + 6*a^4*c*e*f^3 - 8*
a^3*b*d*e^3*f + 26*a*b^3*c*e^4*n - 11*a^4*c*e*f^3*n + 36*a^2*b^2*c*e^3*f - 24*a^3*b*c*e^2*f^2 - 9*a*b^3*c*e^4*
n^2 + a*b^3*c*e^4*n^3 - 7*a^2*b^2*d*e^4*n + 6*a^4*c*e*f^3*n^2 - a^4*c*e*f^3*n^3 - 3*a^4*d*e^2*f^2*n + a^2*b^2*
d*e^4*n^2 + a^4*d*e^2*f^2*n^2 + 24*a^2*b^2*c*e^3*f*n^2 - 21*a^3*b*c*e^2*f^2*n^2 - 3*a^2*b^2*c*e^3*f*n^3 + 3*a^
3*b*c*e^2*f^2*n^3 + 10*a^3*b*d*e^3*f*n - 57*a^2*b^2*c*e^3*f*n + 42*a^3*b*c*e^2*f^2*n - 2*a^3*b*d*e^3*f*n^2))/(
(a*f - b*e)^4*(a + b*x)^n*(35*n^2 - 50*n - 10*n^3 + n^4 + 24)) + (b*f*x^3*(e + f*x)^(n - 5)*(3*b*c*f - 4*a*d*f
+ b*d*e + a*d*f*n - b*d*e*n)*(20*b^2*e^2 - a^2*f^2*n - 9*b^2*e^2*n + a^2*f^2*n^2 + b^2*e^2*n^2 + 10*a*b*e*f*n
- 2*a*b*e*f*n^2))/((a*f - b*e)^4*(a + b*x)^n*(35*n^2 - 50*n - 10*n^3 + n^4 + 24)) + (2*b^2*f^2*x^4*(e + f*x)^
(n - 5)*(5*b*e + a*f*n - b*e*n)*(3*b*c*f - 4*a*d*f + b*d*e + a*d*f*n - b*d*e*n))/((a*f - b*e)^4*(a + b*x)^n*(3
5*n^2 - 50*n - 10*n^3 + n^4 + 24))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*(f*x+e)**(-5+n)/((b*x+a)**n),x)

[Out]

Timed out

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